j^2+5j+4=

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Solution for j^2+5j+4= equation:


Simplifying
j2 + 5j + 4 = 0

Reorder the terms:
4 + 5j + j2 = 0

Solving
4 + 5j + j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(4 + j)(1 + j) = 0

Subproblem 1

Set the factor '(4 + j)' equal to zero and attempt to solve: Simplifying 4 + j = 0 Solving 4 + j = 0 Move all terms containing j to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + j = 0 + -4 Combine like terms: 4 + -4 = 0 0 + j = 0 + -4 j = 0 + -4 Combine like terms: 0 + -4 = -4 j = -4 Simplifying j = -4

Subproblem 2

Set the factor '(1 + j)' equal to zero and attempt to solve: Simplifying 1 + j = 0 Solving 1 + j = 0 Move all terms containing j to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + j = 0 + -1 Combine like terms: 1 + -1 = 0 0 + j = 0 + -1 j = 0 + -1 Combine like terms: 0 + -1 = -1 j = -1 Simplifying j = -1

Solution

j = {-4, -1}

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